既然是變出平方,就試著把a - b + c = 1兩邊同時平方 (a - b + c)^2 = 1^2 = 1
左邊展開得到 a^2 + b^2 + c^2 -2ab + 2ac - 2bc 右邊還是1
整理 => (a^2 + b^2 + c^2) -2(ab - ac + bc) = 1
=> 9 -2(ab - ac + bc) = 1
=> 2(ab - ac + bc) = 8
=> ab - ac + bc = 4
參考資料
自己
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